Calculate the volume occupied by 12.0 g of propane gas at 60°C and 740 mm of pressure. (Molecular weight of C = 12 g/mol , H = 1 g/mol ) [R = 0.082 L atm/molK]
Calculate the volume occupied by 12.0 g of propane gas at 60°C and 740 mm of pressure. (Molecular weight of C = 12 g/mol , H = 1 g/mol ) [R = 0.082 L atm/molK]
Mol wt of propane = 44 g and weight of propane = 12.0 g
So, using PV = nRT
V = (nRT)/P = (12/44) * 0.082 * 333) / (740/760) = 7.648 L
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