The product obtained from the electrolytic oxidation of acidified sulphate solutions, is:
The product obtained from the electrolytic oxidation of acidified sulphate solutions, is:
Main product of electrolysis of conc. H? SO? is H? S? O? i.e. HO? SO-OSO? H
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Mol wt of propane = 44 g and weight of propane = 12.0 g
So, using PV = nRT
V = (nRT)/P = (12/44) * 0.082 * 333) / (740/760) = 7.648 L
To decompose 1 mole of H? O, we need two moles of electrons i.e. 2 faraday
To decompose 4 moles of H? O, we need 8 faraday.
Now, Q = I × t? t = (8 × 96500) / 4 = 1.93×10? sec
Matching Calcium Compounds to their Description:
o Ca (OCl)? : Bleach
o CaSO? • ½ H? O: Plaster of paris
o CaO: Component of cement
o CaCO? : Antacid
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