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Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?

Option 1 -

It will not prefer to undergo redox reactions.

Option 2 -

It will to gain electron and act as an oxidizing agent

Option 3 -

It will prefer to give away an electron and behave as reducing agent

Option 4 -

It acts as both, oxidizing and reducing agent.

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    3 weeks ago
    Correct Option - 2


    Detailed Solution:

    Cerium exists in two oxidation states (+3) and (+4)

      C e + 4 + e − → C e + 3 E 0 = 1 . 6 1 V C e + 3 + 3 e − → C e E 0 = − 2 . 3 3 6 V  

    It exist as Ce+4 and acts like a strong oxidizing agent by gaining electrons

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