Complete combustion of 3 g of ethane gives x×10²² molecules of water. The value of x is _____. (Round off to the nearest integer).
[ Use : NA = 6.023 ×10²³; Atomic masses in u: C:12.0,O:16.0; H:1.0]
Complete combustion of 3 g of ethane gives x×10²² molecules of water. The value of x is _____. (Round off to the nearest integer).
[ Use : NA = 6.023 ×10²³; Atomic masses in u: C:12.0,O:16.0; H:1.0]
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1 Answer
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Combustion of ethane: C? H? + 7/2 O? → 2CO? + 3H? O.
Moles of C? H? = 3g / 30 g/mol = 0.1 mol.
Moles of H? O produced = 0.3 mol.
Number of H? O molecules = 0.3 × 6.023 × 10²³ ≈ 18.06 × 10²².
So, x = 18.
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