Compound A contains 8.7% Hydrogen, 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is,
Given : Atomic masses of C,H and N are 12, 1 and 14 amu respectively. The molar mass of the compound A is 162 g mol-1.
Compound A contains 8.7% Hydrogen, 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is,
Given : Atomic masses of C,H and N are 12, 1 and 14 amu respectively. The molar mass of the compound A is 162 g mol-1.
Empirical formula is C5H7N
Empirical mass = 81
Molecular mass = 162
So, molecular formula is C10H14N2
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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