Compound 'A' with molecular formula C4H9Br is treated with aq. KOH solution. The rate of this reaction depends upon the concentration of the compound 'A' only. When another optically active isomer 'B' of this compound was treated with aq. KOH solution, the rate of reaction was found to be dependent on concentration of compound and KOH both.
(i) Write down the structural formula of both compounds ' A' and ' B '.
(ii) Out of these two compounds, which one will be converted to the product with inverted configuration.
Compound 'A' with molecular formula C4H9Br is treated with aq. KOH solution. The rate of this reaction depends upon the concentration of the compound 'A' only. When another optically active isomer 'B' of this compound was treated with aq. KOH solution, the rate of reaction was found to be dependent on concentration of compound and KOH both.
(i) Write down the structural formula of both compounds ' A' and ' B '.
(ii) Out of these two compounds, which one will be converted to the product with inverted configuration.
This is a short answer type question as classified in NCERT Exemplar
(i) Because the rate of reaction of compound 'A' with aqueous KOH is solely dependent on the concentration of 'A, ' the reaction mechanism is SN1and 'A' is 2-Bromo-2-methylpropane (tertiary bromide).
'B', on the other hand, is an is
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Ten 2025
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