Consider that d? metal ion (M²?) forms a complex with aqua ligands, and the spin only magnetic moment of the complex is 4.90BM. The geometry and the crystal field stabilization energy of the complex is:
Consider that d? metal ion (M²?) forms a complex with aqua ligands, and the spin only magnetic moment of the complex is 4.90BM. The geometry and the crystal field stabilization energy of the complex is:
Since spin only magnetic moment is 4.90BM so number of unpaired electrons must be 4, so If the complex is octahedral, then it has to be high spin complex with configuration t? g? e²g¹ in that case
CFSE = 4* (-0.4Δ? ) + 2*0.6Δ? = -0.4Δ?
If the complex is tetrahedral then its electronic configuration w
Similar Questions for you
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
Rate of ESR ∝ No. of α – H (Hyperconjugation)
Cr3+ion is a most stable in aqueous solution due to. t2g half filled configuration
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry Coordination Compounds 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering



