Consider the following reaction

M n O 4 + 8 H + + 5 e M n + 2 + 4 H 2 O , E ° = 1 . 5 1 V .

The quantity of electricity required is Faraday to reduce five moles of M n O 4  is--------.

(Integer answer)

4 Views|Posted 5 months ago
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5 months ago

MnO4+8H+5eMn+4H2OEo=1.51V

Quantity of electricity required to reduce 1 mole of MnO4 is 5F

So, for 5 mole MnO4 25F electricity is required.

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ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

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Chemistry Electrochemistry 2025

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