Consider the ions /molecule
For increasing bond order the correct option is:
Consider the ions /molecule
For increasing bond order the correct option is:
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>+</mo> </mrow> </msubsup> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>+</mo> </mrow> </msubsup> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>+</mo> </mrow> </msubsup> <mo><</mo> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mo>+</mo> </mrow> </msubsup> <mo><</mo> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msubsup> <mo><</mo> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> </mrow> </math> </span></p>
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4 months ago
Correct Option - 1
Detailed Solution:
Hence Bond order for
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Chemical Bonding and Molecular Structure 2025
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