Consider the ions /molecule

$O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}$

For increasing bond order the correct option is:

Option 1 -

$O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}$

Option 2 -

$O_{2}^{-} < O_{2}^{2 -} < O_{2} < O_{2}^{+}$

Option 3 -

$O_{2}^{-} < O_{2}^{2 -} < O_{2}^{+} < O_{2}$

Option 4 -

$O_{2}^{-} < O_{2}^{+} < O_{2}^{2 -} < O_{2}$

2 Views | Posted 3 weeks ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

3 weeks ago

Correct Option - 1

Detailed Solution:

$B o n d o r d e r = \frac{e^{-} o f B o n d i n g M O - e^{-} o f A B M O}{2}$

Hence Bond order for $O_{2}^{+} = \frac{10 - 5}{2} = 2.5$

$O_{2} = \frac{10 - 6}{2} = 2.0$

$O_{2}^{-} = \frac{10 - 7}{2} = 1.5$

$O_{2}^{- -} = \frac{10 - 8}{2} = 1.0$

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Consider the ions /molecule

$O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}$

For increasing bond order the correct option is:

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Consider the ions /molecule O 2 + , O 2 , O 2 − , O 2 2 − For increasing bond order the correct option is:

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Consider the ions /molecule

$O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}$

For increasing bond order the correct option is: