Cu(s) + Sn2+(0.001M) ® Cu2+ (0.01M) + Sn(s)
The Gibbs free energy change for the above reaction at 298 K is x * 10-1 KJmol-1. The value of x is __________. (nearest integer)
[Given : 0.34V; =96500 Cmol-1]
Cu(s) + Sn2+(0.001M) ® Cu2+ (0.01M) + Sn(s)
The Gibbs free energy change for the above reaction at 298 K is x * 10-1 KJmol-1. The value of x is __________. (nearest integer)
[Given : 0.34V; =96500 Cmol-1]
4 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
V
Answered by
8 months ago
cell reaction is ;
the nearest integer = 983
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Two 2025
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