Ethylene chloride and ethylidene chloride are isomers. Identify the correct statements.

(i) Both the compounds form the same product on treatment with alcoholic KOH.

(ii) Both the compounds form the same product on treatment with aq.NaOH.

(iii) Both the compounds form the same product on reduction.

(iv) Both the compounds are optically active.

<p><span data-teams="true">This is a multiple choice answer as classified in NCERT Exemplar</span></p><p>Isomers are ethylene chloride <strong>ClCH₂-CH₂Cl</strong> and ethylidene dichloride <strong>CH₃-CHCl₂</strong>. Because the carbon atoms are not surrounded by distinct groups, neither molecule is optically active. When haloalkanes are treated with alcoholic <strong>KOH</strong>, they undergo an elimination process in which a hydrogen atom from the -carbon atom and a halogen atom from the -carbon atom are eliminated. To form the ethyne molecule, each of these chemicals lose hydrogen and chlorine atoms. When exposed to aqueous <strong>NaOH</strong>, the molecules undergo nucleophilic substitution, with the –Cl groups being replaced by <strong>-OH</strong> molecules. The results will differ due to the locations of the halides on various carbon atoms.</p><p><strong>Correct Answer:</strong> Option (i) and (iii)</p>

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