Following data is given for the reaction: CaCO3 (s) → CaO (s) + CO2 (g)
∆fHᶱ [CaO(s)] = – 635.1 kJ mol–1
∆fHᶱ[CO2(g)] = – 393.5 kJ mol–1
∆fHᶱ[CaCO3(s)] = – 1206.9 kJ mol–1
Predict the effect of temperature on the equilibrium constant of the above reaction.
Following data is given for the reaction: CaCO3 (s) → CaO (s) + CO2 (g)
∆fHᶱ [CaO(s)] = – 635.1 kJ mol–1
∆fHᶱ[CO2(g)] = – 393.5 kJ mol–1
∆fHᶱ[CaCO3(s)] = – 1206.9 kJ mol–1
Predict the effect of temperature on the equilibrium constant of the above reaction.
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: ΔrH?= ?fH? [CaO(s)]+ ?fH?[CO2(g)]− ?fH?[ [CaCO3(s)]
∴ ?fH? =178.3kJ mol−1.
The reaction is endothermic. Hence, according to Le Chatelier's principle, reaction will proceed in forward direction on increasing temperature.
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025
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