For a given chemical reaction <math> <mrow> <msub> <mrow> <mi>γ</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <mi>A</mi> <mo>+</mo> <msub> <mrow> <mi>γ</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mi>B</mi> <mo>→</mo> <msub> <mrow> <mi>γ</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> <mi>C</mi> <mo>+</mo> <msub> <mrow> <mi>γ</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msub> <mi>D</mi> </mrow> </math> Concentration of C charges form 10 mmol dm-3 to 20 mmol dm-3 in 10 second. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm-3 s-1. Therefore the rate of reaction is_____________mmol dm-3 s-1 (Nearest Integer)

d [ C ] d t = ( 2 0 − 1 0 1 0 ) = 1 m m o l d m − 3 + d [ D ] d t = { − d ( B ) d t } × 1 . 5 = 3 2 { − d [ B ] d t } { − d [ B ] d t } = 2 × { − d [ A ] d t } ∴ 1 6 { − d [ B ] d t } = 1 3 { − d [ A ] d t } = 1 9 { + d [ D ] d t } = d [ C ] d t ∴ rate of reaction = + d [ C ] d t = 1m.m dm-3 S-1

Ask & Answer Question

Chemistry NCERT Exemplar Solutions Class 11th Chapter Four Chemistry Class 12th Chemistry Chemical Kinetics

For a given chemical reaction $γ_{1} A + γ_{2} B \to γ_{3} C + γ_{4} D$ Concentration of C charges form 10 mmol dm^-³ to 20 mmol dm^-³ in 10 second. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm^-³ s^-¹. Therefore the rate of reaction is_____________mmol dm^-³ s^-¹ (Nearest Integer)

12 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

a month ago

$\frac{d [C]}{d t} = (\frac{20 - 10}{10}) = 1 m m o l d m^{- 3}$

$+ \frac{d [D]}{d t} = {- \frac{d (B)}{d t}} \times 1.5 = \frac{3}{2} {- \frac{d [B]}{d t}}$

${- \frac{d [B]}{d t}} = 2 \times {\frac{- d [A]}{d t}}$

$∴ \frac{1}{6} {\frac{- d [B]}{d t}} = \frac{1}{3} {\frac{- d [A]}{d t}} = \frac{1}{9} {\frac{+ d [D]}{d t}} = \frac{d [C]}{d t}$

$∴$ rate of reaction = $\frac{+ d [C]}{d t}$ = 1m.m dm^-3 S^-1

<math> <mrow> <mfrac> <mrow> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>C</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> <mo>=</mo> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>2</mn> <mn>0</mn> <mo>−</mo> <mn>1</mn> <mn>0</mn> </mrow> <mrow> <mn>1</mn> <mn>0</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> <mo>=</mo> <mn>1</mn> <mi>m</mi> <mi>m</mi> <mi>o</mi> <mi>l</mi> <mi>d</mi> <msup> <mrow> <mi>m</mi> </mrow> <mrow> <mo>−</mo> <mn>3</mn> </mrow> </msup> </mrow> </math> <math> <mrow> <mo>+</mo> <mfrac> <mrow> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>D</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> <mo>=</mo> <mrow> <mo>{</mo> <mrow> <mo>−</mo> <mfrac> <mrow> <mi>d</mi> <mrow> <mo>(</mo> <mrow> <mi>B</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> <mo>×</mo> <mn>1</mn> <mo>.</mo> <mn>5</mn> <mo>=</mo> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mrow> <mo>{</mo> <mrow> <mo>−</mo> <mfrac> <mrow> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>B</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> </mrow> </math> <math> <mrow> <mrow> <mo>{</mo> <mrow> <mo>−</mo> <mfrac> <mrow> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>B</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> <mo>=</mo> <mn>2</mn> <mo>×</mo> <mrow> <mo>{</mo> <mrow> <mfrac> <mrow> <mo>−</mo> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>A</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> </mrow> </math> <math> <mrow> <mo>∴</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>6</mn> </mrow> </mfrac> <mrow> <mo>{</mo> <mrow> <mfrac> <mrow> <mo>−</mo> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>B</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> <mrow> <mo>{</mo> <mrow> <mfrac> <mrow> <mo>−</mo> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>A</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>9</mn> </mrow> </mfrac> <mrow> <mo>{</mo> <mrow> <mfrac> <mrow> <mo>+</mo> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>D</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> <mo>}</mo> </mrow> <mo>=</mo> <mfrac> <mrow> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>C</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> </math> <math> <mrow> <mo>∴</mo> </mrow> </math> rate of reaction = <math> <mrow> <mfrac> <mrow> <mo>+</mo> <mi>d</mi> <mrow> <mo>[</mo> <mrow> <mi>C</mi> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mi>d</mi> <mi>t</mi> </mrow> </mfrac> </mrow> </math>  = 1m.m dm-3 S-1

0 Upvotes 0 Downvotes

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
687k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

1 Answer

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question