For the coagulation of a negative sol, the species below, that has the highest flocculating power is:

Option 1 - <p>PO₄³⁻</p>
Option 2 - <p>Na⁺</p>
Option 3 - <p>Ba²⁺<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>SO₄²</p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 2
Detailed Solution:

For the coagulation of a negative sol, the species Ba²? has the highest flocculating power (referring to the Hardy-Schulze rule, where higher charge leads to greater coagulation power).

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

0.01 M NaOH,

M = 1 * 10-2

pOH = 2

pH = 2

A(g) ->B(g) + 1 2 (g)

Initial moles             n                         0       &nbs

...Read more

On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Chemical Equilibrium 2025

Chemistry Chemical Equilibrium 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering