For the coagulation of a negative sol, the species below, that has the highest flocculating power is:
For the coagulation of a negative sol, the species below, that has the highest flocculating power is:
Option 1 -
PO₄³⁻
Option 2 -
Na⁺
Option 3 -
Ba²⁺
Option 4 -
SO₄²
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1 Answer
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Correct Option - 2
Detailed Solution:For the coagulation of a negative sol, the species Ba²? has the highest flocculating power (referring to the Hardy-Schulze rule, where higher charge leads to greater coagulation power).
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0.01 M NaOH,
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36 * 10–2 = Kc (0.0821 * 300)–1
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A(g) ->B(g) + (g)
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