For the reaction
H2F2(g) ® H2(g) + F2(g)
The enthalpy change for the above reaction is ()__________kJ mol-1. [nearest integer]
For the reaction
H2F2(g) ® H2(g) + F2(g)
The enthalpy change for the above reaction is ()__________kJ mol-1. [nearest integer]
Similar Questions for you
3CaO + 2Al → 3Ca + Al? O?
ΔH? = ΣΔH? (Products) - ΣΔH? (Reactants)
ΔH? = [ (0) + (-1675) ] - [ (3 × -635) + (0) ]
ΔH? = -1675 - (-1905) = -1675 + 1905 = 230 kJ
Ans = 230
Water has only two lone pair and XeF4 has two lone pair electron in opposite plane of the central atom.
85gm NH3 = 5 moles of NH3
Enthalpy change for 1 mol = 23.4 kJ
Then enthalpy change for 5 mol = 23.4 * 5 = 117 kJ
Number of moles of C =
State functions are
(a) Internal energy
(b) Volume
(c) Enthalpy
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Six 2025
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