17.0g of NH3 completely vapourises at -33.42°C and 1 bar pressure and the enthalpy change the process is 23.4 kJ mol-1. The enthalpy change for the vapourisation of 85g of NH3 under the same conditions is_____ kJ.
17.0g of NH3 completely vapourises at -33.42°C and 1 bar pressure and the enthalpy change the process is 23.4 kJ mol-1. The enthalpy change for the vapourisation of 85g of NH3 under the same conditions is_____ kJ.
85gm NH3 = 5 moles of NH3
Enthalpy change for 1 mol = 23.4 kJ
Then enthalpy change for 5 mol = 23.4 * 5 = 117 kJ
Similar Questions for you
3CaO + 2Al → 3Ca + Al? O?
ΔH? = ΣΔH? (Products) - ΣΔH? (Reactants)
ΔH? = [ (0) + (-1675) ] - [ (3 × -635) + (0) ]
ΔH? = -1675 - (-1905) = -1675 + 1905 = 230 kJ
Ans = 230
Water has only two lone pair and XeF4 has two lone pair electron in opposite plane of the central atom.
Number of moles of C =
State functions are
(a) Internal energy
(b) Volume
(c) Enthalpy
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry NCERT Exemplar Solutions Class 12th Chapter Five 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering