For water   Δ v a p H = 4 1 k J m o l 1 at 373K and 1 bar pressure. Assuming that water vapour is an ideal gas that occupies a much larger volume than liquid water, the internal energy change during evaporation of water is_________kJ mol-1. [Use: R = 8.3 J mol-1 K-1]

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8 months ago

Δ H v a p = 4 1 K J m o l 1

Δ H = Δ E + Δ n R T      

H 2 O ( l ) H 2 O v a p        

Δ n = 1             

R = 8.3 JK-1 mol-1

T = 373 K

Δ E (Change of internal energy) = Δ H Δ n R T  

? Δ E = 4 1 1 * 8 . 3 * 3 7 3 1 0 0 0 k J m o l 1 = 4 1 3 . 0 9 k J m o l 1 = 3 7 . 9 1 k J m o l 1  

Nearest integer = 38.

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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