Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.
Gases
Critical temperature in Kelvin
H2
33.2
He
5.3
O2
154.3
N2
126
From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first
(i) H2, He, O2, N2
(ii) He, O2, H2, N2
(iii) N2, O2, He, H2
(iv) O2, N2, H2, He
Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.
|
Gases |
Critical temperature in Kelvin |
|
H2 |
33.2 |
|
He |
5.3 |
|
O2 |
154.3 |
|
N2 |
126 |
From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first
(i) H2, He, O2, N2
(ii) He, O2, H2, N2
(iii) N2, O2, He, H2
(iv) O2, N2, H2, He
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
Option (iv) O2, N2, H2, He
Higher the critical temperature of gases more easily, the gas will be liquefied. So, the order of liquefying of gases will be O2 > N2 > H2 >He.
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