Give plausible explanation for each of the following:

(i) Cyclohexanone forms cyanohydrin in good yield but 2,2,6-trimethylcyclohexanone does not.

(ii) There are two –NH2 groups in semicarbazide. However, only one is involved in the formation of semicarbazones.

(iii) During the preparation of esters from a carboxylic acid and an alcohol in the presence of an acid catalyst, the water or the ester should be removed as soon as it is formed.

0 35 Views | Posted 4 months ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    1. Cyclohexanone forms cyanohydrin in good yield because the ketonic group has very less steric hindrance at both the ortho position but 2,2,6 tri methyl cyclohexanone have high steric hindrance which reduces the attack from CN nucleophile.

    2. Only one Amino group is involved in the resonance structure of semicarbazide hence e- density on NH2 group decreases & it can't act as a nucleophile. But another NH2 group can attack as a nucleophile to form semicarbazones.
    3. It is the reversible reaction hence if we don't remove the water or ester the reaction may proceed in backward direction, for that It is essential the water or

    ...more

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