Given below are the statements about diborane.

(A) Diborane is prepared by the oxidation of NaBH₄ With I₂.

(B) Each boron atom is in sp³ hybridized state.      

(C) Diborane has one bridged 3 centre – 2 - electron  bond.

(D) Diborane is a planar molecule.

The option with correct statement(s) is:

Correct Option - 1


Detailed Solution:

$2NaB{H}_4+l_2\to 2Nal+H_2+B_2{H}_6$

Diborane is produced when NaBH₄ is reacted with I₂

Both boron atoms are sp³ hybridised & molecule is non-planar. Diborane as two bridged 3 centre-2-electron bonds.

 

<p>&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1816174916"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;</p><p><span contenteditable="false"> <math> <mrow> <mn>2</mn> <mi>N</mi> <mi>a</mi> <mi>B</mi> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msub> <mo>+</mo> <msub> <mrow> <mi>l</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>→</mo> <mn>2</mn> <mi>N</mi> <mi>a</mi> <mi>l</mi> <mo>+</mo> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>+</mo> <msub> <mrow> <mi>B</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>6</mn> </mrow> </msub> </mrow> </math> </span></p><p>Diborane is produced when NaBH₄ is reacted with I₂</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1754649523phpK2CPkK.jpeg" alt="" width="423" height="187" loading="lazy"></picture></div><div>Both boron atoms are sp³ hybridised &amp; molecule is non-planar. Diborane as two bridged 3 centre-2-electron bonds.</div></div><p>&nbsp;</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment