Given below are two statements : One is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Zero orbital overlap is an out of phase overlap.

Reason R: It results due to different orientation / direction of approach or orbitals.                                                                     

In the light of the above statements, choose the correct answer from the options given below

In sulphide ore, depressants selectively prevent impurity from coming to the fourth.

Radius of Bohr’s orbit $R_n=0.529\stackrel{o}{A}\times \frac{n^2}{z}$

Radius of Bohr’s orbit for hydrogen,  $R_n=0.529\stackrel{o}{A}\times n^2$

For third orbit (R₃) = $0.529\stackrel{o}{A}\times 9$ = r₃ and

Fourth orbit (R₄) = $0.59\stackrel{o}{A}\times 16=r_4$

$\therefore r_4=\frac{16r_3}{9}$

Covalent character is $LiC\mathcal{l}>NaC\mathcal{l}>KC\mathcal{l}>CsC\mathcal{l}.$ As the cationic size increases polarization decreases.

$\therefore$ Covalent character decreases.

Hybridization of P in PF₅ is sp³d, so value of y = 1.

SCl₂ – 2 lone pair of central atom

O₃ – 1 lone pair of central atom

ClF₃ – 2 lone pair of central atom

SF₆ – 0 lone pair of central atom