Given below are two statements:

Statement I : Colourless cupric metaborate is reduced to cuprous metaborate in a luminous flame.

Statement II :  Cuprous metaborate is obtained by heating boric anhydride and copper sulpahte in a non-luminous flame.

In the light of the above statements, choose the most appropriate answer from the options given below

Blue cupric metaborate is reduced to cuprous metaborate in a luminous flame.

$2Cu{\left(B{O}_2\right)}_2+2NaB{O}_2+C\underset{}{\overset{Luminous}{\to }}2CuB{O}_2+N{a}_2{B}_4{O}_7+CO$            

Cupric metaborate is obtained by heating boric anhydride & copper sulphate in a non-luminous flame as

$CuS{O}_4+B_2{O}_3\underset{}{\overset{Non-LuminiousFlame}{\to }}\underset{Blue}{Cu{\left(B{O}_2\right)}_2}+S{O}_3.$