Given below are two statements:

Statement I : [ N i ( C N ) 4 ] 2  is square planar and diamagnetic complex, with dsp2 hybridizatin for Ni but [ N i ( C O ) 4 ]  is tetrahedral, paramagnetic and with sp3 hybridization for Ni.

Statement II : [ N i C l 4 ] 2 a n d [ N i ( C O ) 4 ]  both have same d-electron configuration have same geometry and are paramagnetic.

In light the above statements, choose the correct answer from the options given below

Option 1 - <p>Both <strong>Statement I </strong>and <strong>Statement II </strong>are true.</p>
Option 2 - <p>Both <strong>Statement I </strong>and <strong>Statement II </strong>are false.&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p><strong>Statement I </strong>is correct but <strong>Statement II </strong>is false.</p>
Option 4 - <p><strong>Statement I </strong>is incorrect but <strong>Statement II </strong>is true.</p>
2 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
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8 months ago
Correct Option - 2
Detailed Solution:

  [Ni (CN)4]2

CN is strong field ligand

Ni2+=4s03d8

Here;  [Ni (CN)4]2 is square planar and diamagnetic.

[Ni (CO)4]

Ni = 4s23d8Co is strong field ligand.

Here ;  [Ni (CO)4] is tetrahedral and diamagnetic

[Ni (CN)4]2 has 3d8 configuration while  [Ni (CO)4] has 3d10 configuration.

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine 2025

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