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ΔH_f° of CO₂(g), CO(g), N₂O(g) and NO₂(g) in kJ mol⁻¹ respectively is -393, -110, 81 and 34. Calculate the ΔH in kJ for the following reaction :
2NO₂(g) + 3CO(g) → N₂O(g) + 3CO₂(g).

0 3 Views | Posted 4 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    4 weeks ago

    ΔH_rxn = ΔH_f (N? O, g) + 3ΔH_f (CO? , g) – (2ΔH_f NO? , g) – 3ΔH_f (CO, g)
    = 81 + 3× (– 393) – 2 × 34 – 3 (–110)
    = 81 – 1179 – 68 + 330 = – 836 kJ

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