How many pπ–pπ and pπ–dπ bond present in SO3(s):
How many pπ–pπ and pπ–dπ bond present in SO3(s):
Option 1 -
pπ–pπ = 5, pπ–dπ = 2
Option 2 -
pπ–pπ = 10, pπ–dπ = 2
Option 3 -
pπ–pπ = 0, pπ–dπ = 6
Option 4 -
pπ–pπ = 12, pπ–dπ = 2
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:SO3 (s) exist as cyclic trimer ⇒ S3O9
→ sp3, so all bond π–bonds would be of pπ–dπ so pπ–pπ bond = 0
pπ–dπ bonds = 6
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