If the standard molar enthalpy change for combustion of graphite powder is -2.48 * 102kJ mol-1, the amount of heat generated on combustion of 1g of graphite powder is__________ kJ. (Nearest integer)
If the standard molar enthalpy change for combustion of graphite powder is -2.48 * 102kJ mol-1, the amount of heat generated on combustion of 1g of graphite powder is__________ kJ. (Nearest integer)
More enthalpy of combustion of graphite is -2.48 * 102 kJ/mol, that means 2.48 * 102 kJ heat generates when combustion of 1 mol graphite takes place.
So, heat generated on combustion of 1 g graphite
= 20.67 kJ
Ans. is 21 (the nearest integer)
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Ncert Solutions Class 11th 2023
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