If the wavelength for an electron emitted from H-atom is 3.3 * 10^-10m, then energy adsorbed by the electron in its ground state compared to minimum energy required for its escape from the atom, is ___________times. (Nearest integer)

**[Given: h = 6.626 * 10^-34 Js]

Mass of electron = 9.1 * 10^-31 kg**

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Vishal Baghel | Contributor-Level 10

8 months ago

$λ = \frac{h}{\sqrt[]{2 m E}} E = K i n e t i c E n e r g y$

$E = \frac{h^{2}}{2 m λ^{2}}$

$= \frac{{(6.626 * 1 0^{- 34})}^{2}}{2 * 9.1 * 1 0^{- 31} * {(3.3 * 1 0^{- 10})}^{2}}$

= 2.215 * 10^-18

Eabsorbed – Erequired + K. E

$\frac{E a b s o r b e d}{E r e q u i r e d} = 1 + \frac{K . E}{E r e q u i r e d}$

= $= 1 + \frac{2.215 * 1 0^{- 18}}{13.6 * 1.602 * 1 0^{- 19}} = 2.016$

$\approx$ 2

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If the wavelength for an electron emitted from H-atom is 3.3 * 10-10m, then energy adsorbed by the electron in its ground state compared to minimum energy required for its escape from the atom, is ___________times. (Nearest integer) [Given: h = 6.626 * 10-34 Js] Mass of electron = 9.1 * 10-31 kg

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