In a binary compound, atoms of element A form a hcp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is:
In a binary compound, atoms of element A form a hcp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is:
Option 1 -
M₂A₃
Option 2 -
MA₃
Option 3 -
M₄A
Option 4 -
M₄A₃
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2 Answers
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Correct Option - 4
Detailed Solution:o Let the number of atoms of element A be N.
o Tetrahedral voids = 2N.
o Atoms of element M = (2/3) × 2N = 4/3 N.
o The ratio M : A is (4/3 N) : N, which simplifies to 4:3.
o So, the formula of the compound is M? A?
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Correct Option - 4
Detailed Solution:o Let the number of atoms of element A be N.
o Tetrahedral voids = 2N.
o Atoms of element M = (2/3) * 2N = 4/3 N.
o The ratio M : A is (4/3 N) : N, which simplifies to 4:3.
o So, the formula of the compound is M? A?
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