In basic medium $C r O_{4}^{2 -}$ oxidises $S_{2} O_{3}^{2 -}$ to form $S O_{4}^{2 -}$ and itself changes into Cr(OH)₄^-. The volume of 0.154M $C r O_{4}^{2 -}$ required to react with 40mL of 0.25 M $S_{2} O_{3}^{2 -} i s$ -------------- mL.

(Rounded – off to the nearest integer)

3 Views | Posted a month ago

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

$\begin{array}{l} (+ 6) (+ 2) (+ 3) (+ 6) \\ C r {O_{4}}^{- 2} + \underset{}{\underset{?}{S_{2} {O_{3}}^{- 2} \to C r {(O H)}_{4}^{-} + S {O_{4}}^{- 2}}} \end{array}$

O.N.C = 4

n factor of S₂O₃^-- = 8

n factor of CrO₄^-- = 3

$m . e C r O_{4}^{- 2} = m . e . S_{2} O_{3}^{- 2}$

$V \times (0.154 \times 3) = 40 \times (0.25 \times 8) ∴ v = \frac{80}{0.462}$

= 173.16 ml $\approx$ 173 ml

<math> <mtable columnalign="left"> <mtr> <mtd> <mrow> <mrow> <mo>(</mo> <mrow> <mo>+</mo> <mn>6</mn> </mrow> <mo>)</mo> </mrow> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mrow> <mo>(</mo> <mrow> <mo>+</mo> <mn>2</mn> </mrow> <mo>)</mo> </mrow> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mrow> <mo>(</mo> <mrow> <mo>+</mo> <mn>3</mn> </mrow> <mo>)</mo> </mrow> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mtext> </mtext> <mrow> <mo>(</mo> <mrow> <mo>+</mo> <mn>6</mn> </mrow> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mi>C</mi> <mi>r</mi> <msup> <mrow> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mrow> <mo>−</mo> <mn>2</mn> </mrow> </msup> <mo>+</mo> <munder> <munder> <mrow> <msub> <mrow> <mi>S</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <msup> <mrow> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>3</mn> </mrow> </msub> </mrow> <mrow> <mo>−</mo> <mn>2</mn> </mrow> </msup> <mo>→</mo> <mi>C</mi> <mi>r</mi> <msup> <mrow> <msub> <mrow> <mrow> <mo>(</mo> <mrow> <mi>O</mi> <mi>H</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mrow> <mo>−</mo> </mrow> </msup> <mo>+</mo> <mi>S</mi> <msup> <mrow> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mrow> <mo>−</mo> <mn>2</mn> </mrow> </msup> </mrow> <mo stretchy="true">?</mo> </munder> <mrow></mrow> </munder> </mrow> </mtd> </mtr> </mtable> </math>  O.N.C = 4n factor of S2O3-- = 8n factor of CrO4-- = 3 <math> <mrow> <mi>m</mi> <mo>.</mo> <mi>e</mi> <mtext> </mtext> <mtext> </mtext> <mi>C</mi> <mi>r</mi> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>4</mn> </mrow> <mrow> <mo>−</mo> <mn>2</mn> </mrow> </msubsup> <mo>=</mo> <mi>m</mi> <mo>.</mo> <mi>e</mi> <mo>.</mo> <msub> <mrow> <mi>S</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>3</mn> </mrow> <mrow> <mo>−</mo> <mn>2</mn> </mrow> </msubsup> </mrow> </math>         <math> <mrow> <mi>V</mi> <mo>×</mo> <mrow> <mo>(</mo> <mrow> <mn>0</mn> <mo>.</mo> <mn>1</mn> <mn>5</mn> <mn>4</mn> <mo>×</mo> <mn>3</mn> </mrow> <mo>)</mo> </mrow> <mo>=</mo> <mn>4</mn> <mn>0</mn> <mo>×</mo> <mrow> <mo>(</mo> <mrow> <mn>0</mn> <mo>.</mo> <mn>2</mn> <mn>5</mn> <mo>×</mo> <mn>8</mn> </mrow> <mo>)</mo> </mrow> <mtext> </mtext> <mo>∴</mo> <mi>v</mi> <mo>=</mo> <mfrac> <mrow> <mn>8</mn> <mn>0</mn> </mrow> <mrow> <mn>0</mn> <mo>.</mo> <mn>4</mn> <mn>6</mn> <mn>2</mn> </mrow> </mfrac> </mrow> </math>       = 173.16 ml <math> <mrow> <mo>≈</mo> </mrow> </math> 173 ml

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In basic medium $C r O_{4}^{2 -}$ oxidises $S_{2} O_{3}^{2 -}$ to form $S O_{4}^{2 -}$ and itself changes into Cr(OH)₄^-. The volume of 0.154M $C r O_{4}^{2 -}$ required to react with 40mL of 0.25 M $S_{2} O_{3}^{2 -} i s$ -------------- mL.

(Rounded – off to the nearest integer)

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In basic medium C r O 4 2 − oxidises S 2 O 3 2 − to form S O 4 2 − and itself changes into Cr(OH)4-. The volume of 0.154M C r O 4 2 − required to react with 40mL of 0.25 M S 2 O 3 2 − i s -------------- mL. (Rounded – off to the nearest integer)

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In basic medium $C r O_{4}^{2 -}$ oxidises $S_{2} O_{3}^{2 -}$ to form $S O_{4}^{2 -}$ and itself changes into Cr(OH)₄^-. The volume of 0.154M $C r O_{4}^{2 -}$ required to react with 40mL of 0.25 M $S_{2} O_{3}^{2 -} i s$ -------------- mL.

(Rounded – off to the nearest integer)