In Carius method for estimation of halogens, 0.2g of an organic compound gave 0.188g of AgBr. The percentage of bromine in the compound is_________. (Nearest integer)

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Vishal Baghel | Contributor-Level 10

7 months ago

Mass of organic compound = 0.2 gram

$n_{A g B r} = \frac{0.188}{188} m o l$

= 0.001 mol

$n_{B r} = n_{A g B r} = 0.001 m o l e$

Mass of Br = 0.001 * 80g

= 0.08 g

Mass & of Br = $\frac{0.08}{0.2} * 100 %$

= 40 %

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