In the following the correct bond order sequence is:
In the following the correct bond order sequence is:
O? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px¹ = π2py¹
O? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px¹
O? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px² = π2py¹
O? ²? = σ1s² σ1s² σ2s² σ2s² σ2pz² π2px² = π2py² π2px² = π*2py²
B.O = (Bonding e? - Antibonding e? )/2
B.O of O? = (10 - 6)/2 = 2
B.O of O
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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