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In the sulphur estimation, 0.471 g of an organic compound gave 1.44g of barium sulphate The percentage of sulphur in the compound is________%. (Nearest integer)

(Atomic mass of Ba = 137u).

0 2 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago

    Molar weight of BaSO4 = 233 gram

    233 gm of BaSO4 has 32 gm of S content

    Hence 1.44 gm of BaSO4 has ( 3 2 × 1 . 4 4 2 3 3 ) g of S content = 0.1977 gm of ‘S’

    Weight of sulphur = 0.2 gram (the nearest)

    Weight of organic sample = 0.471 gram

    % of Sulphur = 0 . 2 × 1 0 0 0 . 4 7 1 = 4 2 . 4 6 %  

    the nearest = 42%

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