jkxanJcnlcnqwcnqLCWNQLWCNQLkc
jkxanJcnlcnqwcnqLCWNQLWCNQLkc
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>Z</mi> <mo>=</mo> <mn>1</mn> <mn>1</mn> <mi>x</mi> <mo>+</mo> <mn>7</mn> <mi>y</mi> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mi>x</mi> <mo>+</mo> <mi>y</mi> <mo>≤</mo> <mn>6</mn> <mo>,</mo> <mtext> </mtext> <mi>x</mi> <mo>≤</mo> <mn>2</mn> <mo>,</mo> <mtext> </mtext> <mi>x</mi> <mo>≥</mo> <mn>0</mn> <mo>,</mo> <mtext> </mtext> <mi>y</mi> <mo>≥</mo> <mn>0</mn> <mo>.</mo> </mrow> </math> </span></p>
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Correct Option - 2
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Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry NCERT Exemplar Solutions Class 11th Chapter One 2025
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