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Ka1,  Ka2and  Ka3 are the respective ionization constants for the following reaction (a), (b) and (c).

(A) H2C2O4?H++HC2O4−

(B) HC2O4+?H−+C2O42−

(C) H2C2O4?2H++C2d42−

Option 1 -

K a 2 = K a 1 + K a 2

Option 2 -

K a 2 = K a 1 − K a 2

Option 3 -

K a 3 = K a 1 / K a 2

Option 4 -

K a 3 = K a 1 * K a 2

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    (I) H2C2O4? H++HC2O4−

    (II) HC2O4−? H++C2O42−

    (I) + (II); H2C2O4? 2H++C2O42−

    Ka3=Ka1×Ka2

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