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Match List – I with List – II                                                                                               (Chemical Bonding)

List – I                                          List – II

(A)  [PtCl4]2-                                 (I)   sp3d

(B)  BrF5                                       (II)  d2sp3

(C)  PCl5                                        (III) dsp2

(D)  [Co(NH3)6]3+                         (iv) sp3d2

Choose the most appropriate answer from the options given below :

Option 1 -

(A) – (II) – (B) – (IV), (C) – (I), (D) – (III)

Option 2 -

(A) – (III), (B) – (IV), (C) – (I), (D) – (II)

Option 3 -

(A) – (III), (B) – (I), (C) – (IV), (D) – (II)

Option 4 -

(A) – (II), (B) – (I), (C) – (IV), (D) – (III)

0 25 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 2


    Detailed Solution:

    [ P t C l 4 ] 2 − → P t has dsp2 hybridization

    BrF5 -> Br has sp3d2 hybridization

    PCl5 -> P has sp3d hybridization

    [Co (NH3)6]3+ -> Co has d2sp3 hybridization.

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