Match List – I with List – II:
List – I List – II
(Elements) (Properties)
(A) Ba (i) Organic solvent soluble compounds
(B) Ca (ii) Outer electronic configuration 6s2
(C) Li (iii) Oxalate insoluble in water
(D) Na (iv) Formation of very strong monoacidic base
Choose the correct answer from the options given below:
Match List – I with List – II:
List – I List – II
(Elements) (Properties)
(A) Ba (i) Organic solvent soluble compounds
(B) Ca (ii) Outer electronic configuration 6s2
(C) Li (iii) Oxalate insoluble in water
(D) Na (iv) Formation of very strong monoacidic base
Choose the correct answer from the options given below:
Option 1 -
(A) – (ii), (B) – (iii), (C) – (i) and (D) – (iv)
Option 2 -
(A) – (iv), (B) – (i), (C) – (ii) and (D) – (iii)
Option 3 -
(A) – (i), (B) – (iv), (C) – (ii) and (D) – (iii)
Option 4 -
(A) – (iii), (B) – (ii), (c) – (iv) and (D) – (i)
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1 Answer
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Correct Option - 1
Detailed Solution:Ba has outer electronic configuration 6s2.
CaC2O4 is insoluble in water.
Compound of Li are covalent so soluble in organic solvent.
Na forms strong monoacidic base.
Similar Questions for you
Li+ has the highest hydration enthalpy.
Hence it is most hydrated
Therefore, Correct order of hydrated radii is Cs+ < Rb+ < K+ < Na+ < Li+
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