Number of electron deficient molecules among the following PH3, B2H6, CCl4, NH3, LiH and BCl3 is

Option 1 - <p>0</p>
Option 2 - <p>1</p>
Option 3 - <p>2</p>
Option 4 - <p>3</p>
2 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
R
4 months ago
Correct Option - 4
Detailed Solution:

Number of electrons in

P H 3 = 1 5 + 3 = 1 8  

B 2 H 6 = 5 * 2 + 6 = 1 6  

C C l 4 = 6 + 1 7 * 4 = 6 + 6 8 = 7 4 N H 3 = 7 + 1 * 3 = 1 0 L i H = 3 + 1 = 4 B C l 3 = 5 + 1 7 * 3 = 5 6  

B 2 H 6 & B C l 3  are e- deficient molecules. B2H6 is dimer of BH3, both compound has 6e- only.

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Chemistry Chemical Bonding and Molecular Structure 2025

Chemistry Chemical Bonding and Molecular Structure 2025

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