On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:

Option 1 - <p>+4</p>
Option 2 - <p>+3<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>+2</p>
Option 4 - <p>+5</p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 2
Detailed Solution:

2 Pb (NO? )? → 2PbO + 2NO? + O?
2NO? → N? O? colourless
N? O? + 2NO → 2 N? O?
Oxidation state in N? O? is +3

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Chemistry Redox Reactions 2025

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