PCl₅ ⇌ PCl₃ + Cl₂ Kc = 1.844. 3.0 moles of PCl₅ is introduced in a 1L closed reaction vessel at 380K. The number of moles of PCl₅ at equilibrium is _______ * 10⁻³. (Round off to the Nearest integer)
PCl₅ ⇌ PCl₃ + Cl₂ Kc = 1.844. 3.0 moles of PCl₅ is introduced in a 1L closed reaction vessel at 380K. The number of moles of PCl₅ at equilibrium is _______ * 10⁻³. (Round off to the Nearest integer)
PCl? (g)? PCl? (g) + Cl? (g); Kc = 1.844
t=0: 3, 0, 0
equilibrium: 3-x, x
Kc = x² / (3-x) = 1.844
x² + 1.844x - 5.532 = 0
x = (-1.844 + √ (1.844² - 4 (1) (-5.532)/2 = (-1.844 + √25.528)/2 ≈ 1.604
At equilibrium number of moles of PCl? = (3 - 1.604) = 1.396 mol
= 1396 * 10? ³ mol
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Chemistry Ncert Solutions Class 11th 2023
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