PCl5 dissociates as

PCl5(g) ?  PCl3 (g) + Cl2(g)

5 moles of PCl5 placed in a 200 litre vessel which contains 2 moles of N2 and is maintained at 600K. The equilibrium pressure is 2.46 atm. The equilibrium constant Kp for the dissociation of PCl5 is ____________ × 10-3g.  (nearest integer).

(Given R = 0.082 L atm K-1 mol-1; Assume ideal gas behavior)

0 2 Views | Posted 2 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago

    PCl5(g)?PCl3(g)+Cl2(g)t=05moles00xmole_+xmole_+xmole_

    Eq.(5 – x) mole x molex mole

    Total number of moles at equilibrium

    =(5x)+x+x+nN2=(7+x)

    Kp=(PPCl3)×(PCl2)Cl(PPCl5)eq=(310×2.46)×(310×2.46)(210×2.46)=1.107atm

    = 1107 × 103 atm

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