pH of 0.08 mol dm–3 HOCl solution is 2.85. Calculate its ionisation constant.
pH of 0.08 mol dm–3 HOCl solution is 2.85. Calculate its ionisation constant.
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: pH of HOCL = 2.85
But, - pH = log [H+]
-2.85=log [H+]
= -3.15 = log [H+]
[H+]=anti log3.15
[H+]= 1.413* 10-3
or weak mono basic acid
[H+]= C
= = =
=24.957 10-6
=2.4957 10-5
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven 2025
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