Potassium chlorate is prepared by electrolysis  of KCl in basic solution as shown by following equation.

6 OH- + Cl- C l O 3 ->  + 3H2O + 6e-

A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is__________. (Nearest Integer)

(Molar mass of KClO3 = 122.6g mol-1, F = 96500C)

5 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
V
7 months ago

6 O H + C l C l O 3 + 3 H 2 O + 6 e

Mole of  C l O 3 o r K C l O 3 = 1 0 1 2 2 . 6 = 0 . 8 4 5 6 m o l

1 mole of C l O 3  or KClO3 produced by 6 faraday (F).

0 . 0 8 4 5 6 mole of C l O 3 or KClO3 produced by (6 * 0.08156) F

l * t F = 6 * 0 . 8 1 5 6

l = 6 * 0 . 0 8 1 5 6 * 9 6 5 0 0 0 1 0 * 6 0 * 6 0 A = 1 . 3 1 1 A 1 A

             

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Redox Reactions 2025

Chemistry Redox Reactions 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering