Production of iron in blast furnace follows the following equation

$F{e}_3{O}_4\left(s\right)+4CO\left(g\right)\to 3Fe\left(I\right)+4C{O}_2\left(g\right)$

When 4.640 kg of Fe₃O₄ and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is:

[Given : Molar Atomic mass (g mo^-1); Fe = 56

Molar Atomic mass (g mol^-1); O = 16

Molar Atomic mass (g mol^-1); C = 12]

<p>Moles of Fe₃O₄ = <math><mrow><mfrac><mrow><mn>4</mn><mo>.</mo><mn>6</mn><mn>4</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mn>3</mn></mrow></msup></mrow><mrow><mn>2</mn><mn>3</mn><mn>2</mn></mrow></mfrac><mo>=</mo><mn>2</mn><mn>0</mn></mrow></math></p><p>Moles of CO =&nbsp;<math><mrow><mfrac><mrow><mn>2</mn><mo>.</mo><mn>5</mn><mn>2</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mn>3</mn></mrow></msup></mrow><mrow><mn>2</mn><mn>8</mn></mrow></mfrac><mo>=</mo><mn>9</mn><mn>0</mn></mrow></math></p><p>So limiting reagent = Fe₃O₄</p><p>So moles of Fe formed = 60</p><p>Weight of Fe = 60 × 56 = 3360</p><p>&nbsp;</p>

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