Production of iron in blast furnace follows the following equation

Fe3O4(s)+4CO(g)3Fe(I)+4CO2(g)

When 4.640 kg of Fe3O4 and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is:

[Given : Molar Atomic mass (g mo-1); Fe = 56

Molar Atomic mass (g mol-1); O = 16

Molar Atomic mass (g mol-1); C = 12]

Option 1 - <p>1400</p>
Option 2 - <p>2200</p>
Option 3 - <p>3360</p>
Option 4 - <p>&nbsp;4200</p>
4 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
A
8 months ago
Correct Option - 3
Detailed Solution:

Moles of Fe3O4 = 4.64*103232=20

Moles of CO = 2.52*10328=90

So limiting reagent = Fe3O4

So moles of Fe formed = 60

Weight of Fe = 60 * 56 = 3360

 

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ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Six 2025

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