Class 11th Structure of Atom Chemistry

Quantum number for outermost electron of K-atom are given by

Option 1 - <p><span lang="EN-IN">n = 4, l = 0, m = 0,  </span><span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></p>

Option 2 - <p><span lang="EN-IN">n = 4, l = 1, m = 0,  <span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></span></p>

Option 3 - <p><span lang="EN-IN">n = 3, l = 0, m = 0, </span><span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></p>

Option 4 - <p><span lang="EN-IN">n = 4, l = 0, m = 1,<span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mo>=</mo> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span> </span></p>

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Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 1

Detailed Solution:

K₁₉ = 1s²2s²2p⁶3s²3p⁶4s¹

For 4s electron

n = 4

l = 0

m = 0

$s = \frac{1}{2}$

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