Rate law for the reaction A + 2B→C is found to be
Rate = k[A][B]
Concentration of reactant ‘B’ is doubled, keeping the concentration of ‘A’ constant, the value of rate constant will be______.
A. The same
B. Doubled
C. Quadrupled
D. Halved
Rate law for the reaction A + 2B→C is found to be
Rate = k[A][B]
Concentration of reactant ‘B’ is doubled, keeping the concentration of ‘A’ constant, the value of rate constant will be______.
A. The same
B. Doubled
C. Quadrupled
D. Halved
-
1 Answer
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This is a Fill in the blanks Type Question as classified in NCERT Exemplar
Ans: Correct option A
The rate concentration of a reaction does not depend upon concentrations of the reactions. Hence, it will remain the same. Even if the equation shows the double concentration level even the rate concentration doubles so it’s the same throughout.
Following with the equation
A + 2B→C
If rate considered as (1)
Rate1 = k [A] [B]
If rate considered as 2
Then, Rate1 = k [A] [2B]
Rate2 = 2Rate1
Option A is correct answer
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