Resistance of a conductivity cell (cell constant 129 m-1) filled with 74.5 ppm solution of KCl is 1 0 0 Ω  (labeled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is 5 0 Ω  (labeled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. 1 2 = x * 1 0 3 .  The value of x is________. (Nearest integer)

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8 months ago

Molar mass of C7H5N3O6 = 12 * 7 + 1 * 5 + 14 * 3 + 16 * 6 = 84 + 42 + 96 = 227 g/mol

Number of moles = 6 8 1 2 2 7  = 3 mol

number of N-atoms

=3*6.02*1023*3=9*6.02*1023

=5418*1021

x=5418         

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ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

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Chemistry Electrochemistry 2025

Chemistry Electrochemistry 2025

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