Resistance of a conductivity cell (cell constant 129 m^-1) filled with 74.5 ppm solution of KCl is $100\Omega$  (labeled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is $50\Omega$  (labeled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. $\frac{{\wedge }_1}{{\wedge }_2}=x\times 10^{-3}.$  The value of x is________. (Nearest integer)

<p>Molar mass of C₇H₅N₃O₆= 12 × 7 + 1 × 5 + 14 × 3 + 16 × 6 = 84 + 42 + 96 = 227 g/mol</p><p>Number of moles = <span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>6</mn> <mn>8</mn> <mn>1</mn> </mrow> <mrow> <mn>2</mn> <mn>2</mn> <mn>7</mn> </mrow> </mfrac> </mrow> </math> </span>&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1814875767"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;= 3 mol</p><p><span contenteditable="false"> <math> <mrow> <mo>∴</mo> </mrow> </math> </span>number of N-atoms</p><p><math><mrow><mo>=</mo><mn>3</mn><mo>×</mo><mn>6</mn><mo>.</mo><mn>0</mn><mn>2</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mn>2</mn><mn>3</mn></mrow></msup><mo>×</mo><mn>3</mn><mo>=</mo><mn>9</mn><mo>×</mo><mn>6</mn><mo>.</mo><mn>0</mn><mn>2</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mn>2</mn><mn>3</mn></mrow></msup></mrow></math></p><p><math><mrow><mo>=</mo><mn>5</mn><mn>4</mn><mn>1</mn><mn>8</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mn>2</mn><mn>1</mn></mrow></msup></mrow></math></p><p><math><mrow><mo>∴</mo><mi>x</mi><mo>=</mo><mn>5</mn><mn>4</mn><mn>1</mn><mn>8</mn></mrow></math>&nbsp; &nbsp; &nbsp; &nbsp;&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1029" DrawAspect="Content" ObjectID="_1814875771"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;&nbsp;</p>

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