Section -A

Consider the reaction

4HNO3(l) + 3 KCl(s) ® Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)

The amount of HNO3 required to produce 110.0g of KNO3 is

(Given: Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively)

Option 1 - <p>32.2g</p>
Option 2 - <p>69.4g</p>
Option 3 - <p>91.5g</p>
Option 4 - <p>162.5g</p>
3 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 3
Detailed Solution:

4HNOI3(l)+3KCl(s)Cl2(g)+NOCl(g)+2H2O(g)+3KNO3(g)

             

4 moles of HNO3 produced 3 mol of KNO3

Here mole of produced KNO3 = 1 1 0 1 0 1  

If 3 mol of KNO3 produced by 4 moles of HNO3

 1 mole of KNO3 produced by  4 3 moles of HNO3

and  1 1 0 1 0 1 mole of KNO3 produced by 4 * 1 1 0 3 * 1 0 1  moles of HNO3 = 1.45 mole of HNO3

Hence mass of HNO3 = mole * mol.wt = 145 * 63 =

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Chemistry Some Basic Concepts of Chemistry 2025

Chemistry Some Basic Concepts of Chemistry 2025

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