Section -A
Consider the reaction
4HNO3(l) + 3 KCl(s) ® Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)
The amount of HNO3 required to produce 110.0g of KNO3 is
(Given: Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively)
Section -A
Consider the reaction
4HNO3(l) + 3 KCl(s) ® Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)
The amount of HNO3 required to produce 110.0g of KNO3 is
(Given: Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively)
4 moles of HNO3 produced 3 mol of KNO3
Here mole of produced KNO3 =
If 3 mol of KNO3 produced by 4 moles of HNO3
1 mole of KNO3 produced by moles of HNO3
and mole of KNO3 produced by moles of HNO3 = 1.45 mole of HNO3
Hence mass of HNO3 = mole * mol.wt = 145 * 63 =
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Some Basic Concepts of Chemistry 2025
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