SO2Cl2 on reaction with excess of water results into acidic mixture
SO2Cl2 + H2O ® H2SO4 + 2HCl
16 moles of NaOH is required for the complete neutralization of the resultant acidic mixture. The number of moles of SO2Cl2 used is:
SO2Cl2 on reaction with excess of water results into acidic mixture
SO2Cl2 + H2O ® H2SO4 + 2HCl
16 moles of NaOH is required for the complete neutralization of the resultant acidic mixture. The number of moles of SO2Cl2 used is:
Let a moles of SO2Cl2 is taken
Then no. of moles of H2SO4 = a moles
No. of moles of HCl = 2a moles
No. of moles of NaOH required = 2a + 2a = 4a = 16
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Ncert Solutions Class 11th 2023
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