SO₂Cl₂ on reaction with excess of water results into acidic mixture

SO₂Cl₂ + H₂O ® H₂SO₄ + 2HCl

16 moles of NaOH is required for the complete neutralization of the resultant acidic mixture. The number of moles of SO₂Cl₂ used is:

<p><span contenteditable="false"> <math> <mrow> <mi>S</mi> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mi>C</mi> <msub> <mrow> <mi>l</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mo>+</mo> <mn>2</mn> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mi>O</mi> <mo>→</mo> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mi>S</mi> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msub> <mo>+</mo> <mn>2</mn> <mi>H</mi> <mi>C</mi> <mi>l</mi> </mrow> </math> </span>&nbsp;</p><p><span lang="EN-IN">Let a moles of SO₂Cl₂ is taken</span></p><p>Then no. of moles of H₂SO₄ = a moles</p><p><span lang="EN-IN">No. of moles of HCl = 2a moles</span></p><p><span lang="EN-IN">No. of moles of NaOH required = 2a + 2a = 4a = 16</span></p><p><span lang="EN-IN"><span contenteditable="false"> <math> <mrow> <mo>⇒</mo> <mi>a</mi> <mo>=</mo> <mn>4</mn> <mi>m</mi> <mi>o</mi> <mi>l</mi> <mi>e</mi> <mi>s</mi> </mrow> </math> </span></span>&nbsp;</p>

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