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Spin only magnetic moment of an octahedral complex of Fe2+  in the presence of a strong field ligand in BM is:

Option 1 -

2.82

Option 2 -

3.46

Option 3 -

0

Option 4 -

4.89

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    In strong field of octahedral complex of Fe2+, the electronic configuration is,

    F e 2 6 2 + → [ A r ] 3 d 6 4 s 0

    Number of unpaired electrons are zero in the presence of strong field ligand.

    Hence, spin only magnetic moment = n ( n + 2 ) = 0 B M ( n = 0 )

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