Standard molar enthalpy of formation, ∆fHᶱ is just a special case of enthalpy of reaction, ∆r HV . Is the ∆r HV for the following reaction same as ∆f HV ? Give reason for your answer.
CaO(s) + CO2(g) → CaCO3(s); ∆fHᶱ = –178.3 kJ /mol
Standard molar enthalpy of formation, ∆fHᶱ is just a special case of enthalpy of reaction, ∆r HV . Is the ∆r HV for the following reaction same as ∆f HV ? Give reason for your answer.
CaO(s) + CO2(g) → CaCO3(s); ∆fHᶱ = –178.3 kJ /mol
This is a Short Answer Type Questions as classified in NCERT Exemplar
Standard molar enthalpy of formation, rH1- is just a special case of fH2-, where
one mole of a compound is formed from its constituent elements. In the above equation, enthalpy of formation and enthalpy of reaction is not the same.
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Six 2025
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